8x^2+11x=56

Solution for 8x^2+11x=56 equation:

8x^2+11x=56

We move all terms to the left:

8x^2+11x-(56)=0

a = 8; b = 11; c = -56;
Δ = b2-4ac
Δ = 112-4·8·(-56)
Δ = 1913
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{1913}}{2*8}=\frac{-11-\sqrt{1913}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{1913}}{2*8}=\frac{-11+\sqrt{1913}}{16}
$